find the sum of first n even natural number
Answers
Answered by
21
Even natural numbers = 2,4,6,8,....
d=4-2=2
Sn=n/2[2a+(n-1)d]
Sn=n/2[2×2+(n-1)2]
Sn=n/2[4+2n-2]
Sn=n/2[2n+2]
Sn=2n^2+2n/2
Sn=2(n^2+n)/2
Sn=n^2+n
Sum of first n even natural numbers = n square +n
Hope it helps
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Answered by
3
Answer:
n square +n
Step-by-step explanation:
Even natural numbers = 2,4,6,8,....
d=4-2=2
Sn=n/2[2a+(n-1)d]
Sn=n/2[2×2+(n-1)2]
Sn=n/2[4+2n-2]
Sn=n/2[2n+2]
Sn=2n^2+2n/2
Sn=2(n^2+n)/2
Sn=n^2+n
Sum of first n even natural numbers = n square +n
Hope it helps
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