Question

find the sum of following using column method a2+2ab+b2,a2 -2ab-b2 a2+b2​

Answer 1

SOLUTION:

We have to simply add the given terms.

$( {a}^{2} + 2ab + {b}^{2}) + ( {a}^{2} - 2ab - {b}^{2} ) + ( {a}^{2} + {b}^{2} )$

Now let us open the brackets

${a}^{2} + 2ab + {b}^{2} + {a}^{2} - 2ab - {b}^{2} + {a}^{2} + {b}^{2}$

Let us now arrange the terms on the basis of same variables.

${a}^{2} + {a}^{2} + {a}^{2} + {b}^{2} - {b}^{2} + {b}^{2} + 2ab - 2ab$

${3a}^{2} + {b}^{2} + 0$

${3a}^{2} + {b}^{2}$

Hence, This is the required answer.

Answer 2

Answer:

his answer is correct

Step-by-step explanation:

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