find the sum of Frist multiple of 3
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answer is 3
3 is an first even number
3 is an first even number
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First five multiple of 3 are:
3, 6, 9, 12, 15
Here first term, a = 3
common difference, d = 6 – 3 = 3
Number of term, n = 5
⇒ s5 = 9 × 5 = 45
3, 6, 9, 12, 15
Here first term, a = 3
common difference, d = 6 – 3 = 3
Number of term, n = 5
⇒ s5 = 9 × 5 = 45
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