find the sum of last ten terms of AP 8,10,12.....,126.
Answers
Answered by
550
a/c to question ,
we invert this series ,
126 , 124 , 122 ,........8
now,
first term of new AP is = 126
common difference = -2
use formula,
Sn =n/2 {2a +(n-1)d
S10=10/2{2 × 126 +(10-1)(-2)}
=5{252 -18}
=5 × 234
=1170
we invert this series ,
126 , 124 , 122 ,........8
now,
first term of new AP is = 126
common difference = -2
use formula,
Sn =n/2 {2a +(n-1)d
S10=10/2{2 × 126 +(10-1)(-2)}
=5{252 -18}
=5 × 234
=1170
Answered by
32
Answer:
a/c to question ,
we invert this series ,
126 , 124 , 122 ,........8
now,
first term of new AP is = 126
common difference = -2
use formula,
Sn =n/2 {2a +(n-1)d
S10=10/2{2 × 126 +(10-1)(-2)}
=5{252 -18}
=5 × 234
=1170
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