find the sum of n term of an ap root 2, root 8, root 18, root 32
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Answered by
5
Answer:
sum of n terms= root two +n-1(root 8- root 2
Answered by
39
Answer:
AP
= √2, √8, √18 ,√32 ........
can be also written as
√2, 2√2, 3√2, 4√2,........
here
a = √2 and common difference = √2
Sn = n/2(2a + (n-1)(d))
Sn = n/2(2(√2) + (n-1)(√2))
Sn = (√2)n/2 x ( 2 + n - 1)
Sn = n/√2 x (n + 1)
Sn = n(n+1)/√2
hope this will help you
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