Question

Find the sum of n terms of an ap whose first term is x ,the last term is y and d is 1

Answer 1

Step-by-step explanation:

first term (a) = x , last term(n) = y ,common difference (d) = 1

formula for finding sum of first n terms of an ap is

n{2a + (n-1)d} / 2

where n is last term , a is first term , d is common difference

y(2x + y-1)/2

= 2xy + y^2 - y / 2

Answer 2

Sol:-

Let First term a=x

last term [n] be y\

n/2{2a+[n-1]d}

y{2x+y-1}

2xy+ysquare 2-y