Question

Find the sum of the following APs : -37 , -33 , -29 ,....., to 12 terms

Answer 1

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Here's the answer :

$</em><em>\</em><em>b</em><em>l</em><em>u</em><em>e</em><em>{</em><em>S12</em><em> = </em><em>-</em><em>180</em><em>}</em><em>$

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Answer 2

Given,

a= first term = -37

an = nth term

d= common difference

=> -33 -(-37) , -29-(-33)

=> -33+37 , -29+33

=> 4

n = no. of terms = 12

thus,

Sn = n/2 [2a+( n-1) d]

Sn = 12/2 [ 2× (-37) + 11× 4]

Sn = 6[-74 + 44]

=> 6[-30]

=> -180

alternative method:

an = a + (n-1) d

an = -37 + (11)4

an = -37 + 44 = 7

Sn = n/2 [a + an]

Sn = 12/2 [ -37 +7]

=> 6[-30]

=> -180