Math, asked by chiragmadhusharma, 1 month ago

find the sum of the interior angle of the polygon of-
(a) 8 sides
(b)14 sides​

Answers

Answered by srpuramjyothi
0

Answer:

(i) 9 sides

No of sides = n = 9

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 9 - 4) x 90

= 14 x 90 = 1260

(ii) 13 sides

No of sides = n = 13

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 13 - 4) x 90

= 1260

(iii) 16 sides

No of sides = n = 16

Sum of interior angles of polygon = (2n-4) x 90

= (2 x 16 - 4) x 90

= 28 x 90 = 2520

Answered by panksonsnr
1

Answer:

a) 1080

b) 2160

Step-by-step explanation:

Using the formula (n-2)×180

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