Question

find the sum of the interior angles of a polygon of (a) 6 sides (b) 15 sides
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Answer 1

Answer:

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Answer 2

Answer:

sum of all interior angle = no. of sides × measure of an interior angle

$(a)6 \: sides \\ = n \times (180 - \frac{360}{n} )(n = 6) \\ = 6 \times (180 - \frac{360}{6} ) \\ = 6 \times (180 - 60) \\ = 6 \times 120 \\ = 720 \: degree \\ \\ \\ (b)15 \: sides(n = 15) \\ = n \times (180 - \frac{360}{15} ) \\ = 15 \times (180 - \frac{360 }{15} \\ = 15 \times (180 - 24) \\ = 15 \times 156 \\ = 2340 \: degree$

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