Question

the mass of planet 3 ×10^28 kg and radius 6×10^6 m calculate acceleration due to gravity on surface​

Answer 1

$\huge\mathbb{\orange{QUESTION-}}$

The mass of planet ${\sf 3×10^{28}}$ kg and radius ${\sf 6×10^6}$ m calculate acceleration due to gravity on surface

$\huge\mathbb{\orange{SOLUTION-}}$

$\large\underline{\underline{\sf Given:}}$

• Mass of planet (m) = ${\sf 3×10^{28}}$ kg
• Radius (r) = ${\sf 6×10^6}$ m

$\large\underline{\underline{\sf To\:Find:}}$

• Acceleration due of gravity (g)

$\large\underline{\underline{\sf Formula\:Used:}}$

✪$\large{\boxed{\sf g = \dfrac{Gm}{r^2} }}$

G = Gravitational Constant = ${\sf 6.67×10^{-11}Nm^2/kg^2}$

$\implies{\sf g=\dfrac{6.67×10^{-11}×3×10^{28}}{(6×10^6)^2}}$

$\implies{\sf \dfrac{20.01×10^{17}}{36×10^{12}}}$

$\implies{\bf \red{g= 5.5×10^4m/s^2}}$

$\huge\mathbb{\orange{ANSWER-}}$

Acceleration due to gravity is ${\bf \red{5.5×10^5m/s^2}}$

Answer 2

Answer:

acceleration due to gravity is equal to Gm/r²

=6.67×10-¹¹×3×10^28/(6×10^6)²

you solve this