find the sum of the lengths of the Base of a trapezium whose area is 4.2 m2 and whose height is 280cm
Answers
Answered by
105
Given,
Area of trapezium = 4.2m^2
Height = 280 cm = 2.8m
Sum of lengths = 2 * 4.2/2.8 = 3m
poorvi123:
area of the trapezium is 1 by 2 × sum of parallel sides × by height
Answered by
37
Area = 0.5*(sum of parallel sides)*h
Therefore,
Sum of parallel sides = (4.2*100*100*2)/280 cm
= 300 cm
= 3m
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