Question

find the sum of two digit numbers divisible by 6

I want full answer...

Answer 1

48=4+8=12 which is divisible by 2

Answer 2

All two digit numbers divisible by 6 are:-

12,18,24.................96

This is AP .

We know:

$a_{n}$=a+(n-1)d

So:

96=12+(n-1)*6

84=6n-6

6n=90

n=90/6

=15.

So use this formula to find sum

12+18+24......96

=n/2*[2a+(n-1)d]

=15/2*[24+14*6]

=15/2*[24+84]

=15/2*108

=15*54

=810

Hope it helps you.

Thanks.