Represent the following situation in the form of quadratic equation
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Let the original speed of train be x km/h
then reduced speed is x-8 km/h
ATQ
480/x-8 - 480/x = 3
u can solve it now
then reduced speed is x-8 km/h
ATQ
480/x-8 - 480/x = 3
u can solve it now
RK123111:
It is a big help THANKS
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