Question

find the sum, product of the roots of 6x_7=x2​

Answer 1

6x-7 = x²

=> x²-6x+7 = 0

$= >x = \frac{ - b \binom{ - }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = > x = \frac{ - ( - 6) \sqrt{36 - 4 \times 1 \times 7} }{2 \times 1} \\ \\ = > x = \frac{6 \binom{ + }{ - } \sqrt{36 - 28} }{2} \\ \\ = > x = \frac{6 \binom{ + }{ - }2 \sqrt{2} }{2} \\ \\ = > x = 3 \binom{ + }{ - } \sqrt{2}$

Required values of x : 3+√2 & 3-√2

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