find the sum upto 12 terms 14+10+6+2+...........
arnav98:
Give example pls/.....
use formula for summation of N terms of Arithmetic Progression ...... N is total terms, a is first term, d is common difference, N = 12, a = 14, d = -4 So apply (N/2) * [2a + (N-1)*d] = 6 * [28 - 44] = -96
Anudeep, not number, the sum is -96, kindly correct it ...
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Answered by
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14+10+6+2+(-2)+(-6)+(-10)+(-14)+(-18)+(-22)+(-26)+(-30)
14+10+6+2-2-6-10-14-18-22-26-30
(14+10+6+2)-(2+6+10+14+18+22+26+30)
32-128
-96
14+10+6+2-2-6-10-14-18-22-26-30
(14+10+6+2)-(2+6+10+14+18+22+26+30)
32-128
-96
Answered by
0
so common difference(d)= 10 - 14 = - 4
total terms(n)= 12
first term = 14
so using formula
sum = n/2{2a + (n - 1)d}
solving
sum = 12/2 {2 x 14 +(12 - 1 )(- 4)}
solving we get sum = - 96
total terms(n)= 12
first term = 14
so using formula
sum = n/2{2a + (n - 1)d}
solving
sum = 12/2 {2 x 14 +(12 - 1 )(- 4)}
solving we get sum = - 96
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