Question

Find the sumof odd integers from 1 to 2001​

Answer 1

Answer:

The series of odd integers from 1 to 2001 is,

1 , 3 , 5 , 7.............. ...

a = 1 a=1 a=1.

d = 3 − 1 = 2 d=3-1=2 d=3−1=2.

l = 2001 l=2001 l=2001.

a n = a + ( n − 1 ) d a_n=a+(n-1)d an=a+(n−1)d.

2001 = 1 + ( n − 1 ) 2 2001=1+(n-1)2 2001=1+(n−1)2.

2000 = 2 ( n − 1 ) 2000=2(n-1) 2000=2(n−1)

∴ n = 1001 \therefore n=1001 ∴n=

Step-by-step explanation:

please make me as brainlist....

Answer 2

Step-by-step explanation:

1+3+5...........+2001

an = 2001

2001 =1+(n-1) 2

1000+1 = n

n = 1001

sn = 1001/2 ( 1+2001) = 1001× 1001 = 1,002,001

inshallah it helps uuh...❤