Find the surface area of a chalk box whose length breadth and height 8 cm 4 cm and 2 cm respectively
Answers
Answered by
9
✌✌hey here is ur ans ..✌✌
surface area of chalk box = 2 (lb + bh + hl )
= 2 ( 8×4 + 4×2 + 2×8 )
= 2 ( 32 + 8 + 16 )
= 2 ( 66 )
= 132 cm^2
hope it will help uh ..
nd plz mark as brainliest ..☺☺
surface area of chalk box = 2 (lb + bh + hl )
= 2 ( 8×4 + 4×2 + 2×8 )
= 2 ( 32 + 8 + 16 )
= 2 ( 66 )
= 132 cm^2
hope it will help uh ..
nd plz mark as brainliest ..☺☺
Answered by
10
answer :
surface area of the chalk box : 2 (lb+bh+hl)
=2(8×4+4×2+2×8)
=2 (56)
=112sq.units
tq
surface area of the chalk box : 2 (lb+bh+hl)
=2(8×4+4×2+2×8)
=2 (56)
=112sq.units
tq
nandhini18:
oops sorry the answer is 132
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