find the surface area of a cube with a volume of 19683 meter cube
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Volume of cube = a³ = 19683 m³ => a = ∛19683 = 27 m
Surface Area = 6a² = 6(27)² = 6 × 729 = 4374 m² Ans.
Surface Area = 6a² = 6(27)² = 6 × 729 = 4374 m² Ans.
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Answered by
1
surface area of cube =(a)cube
19683=(a)cube
a=27
surface area =4(a)square
4×27×27
=1916
19683=(a)cube
a=27
surface area =4(a)square
4×27×27
=1916
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