Question

find the thermal capacity of 200 gram of water specific heat capacity of water is 1 calorie per gram degree Celsius​

Answer 1

Answer:

0

Explanation:

Solution:

Sum/Principal = Difference between SI & Cl = SI-CI

=>[P(1+r)^n -P] - (P × R × N)/100 = $40

=>[P(1 + 0.05)² -P] - (10P/100) = $40

=>[P(1.05)² -P ] - (P/10) = $40

=>[P × 1.102 -P]- (P /10) =$40

=>1025P/10000-P/10 = $40

=>25P = 400000

=>P = 400000/25

=>P = $16000

Sum of money=$16,000

_____________________pls follow

Answer 2

Answer:

Sum of money = $16, 000