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Answer 1

Step-by-step explanation:

In ∆ABD,

angle DAE is the exterior angle and,

angle ABD and angle BDA are interior opposite angles.

We know that the exterior angle of a triangle is equal to the sum of it's interior opposites angle.

Therefore,

by the condition,

Angle ABD + Angle BDA=Angle DAE

x +50°= 120°

x=120° - 50°

x= 70°

Hence,

Angle ABD = Angle ACB = 70°

Now,

as angle ACB and Angle ACD form linear pair,

Therefore,

Angle ACB + Angle ACD =180°

70° + y = 180°

y= 180° - 70°

y= 110°

Hope it will help you......