Question

find the total surface area of cuboid whose dimensions are the zeros of X^3-6x^2+11x-6.​

Answer 1

Volume of a cuboid = L * B * H

Since one side = x-1

& volume = x^3 - 6x² + 11x - 6

So, the product of other 2 sides =

( x^3 - 6x² + 11x - 6) ÷ ( x-1)

= quotient = x² - 5x + 6 & remainder has to zero

Now, by factorizing x² - 5x + 6

= (x-3) ( x- 2)

This way , other 2 sides ( we can say its breadth & height) are ( x-2) & (( x-3)

see if it is right army

Answer 2

Answer:

above attachment

Step-by-step explanation:

may be that help u