find the two numbers whose difference is 13 and product is 48
Answers
Answered by
9
Answer:
the 2 numbers are 16 and 3
Answered by
9
Answer:
Value of a= 16, b = 3.
Step-by-step explanation:
Let the two numbers be a and b respectively
According to the given conditions:
a-b = 13 -------(i)
ab = 48 -------(ii)
Solving the two equations we get,
b( 13+b ) = 48 ( substituting value of a from equation i in ii)
So, b^2 + 13b -48 = 0
On solving the quadratic equation we get the value of b as: -16, +3 ( taking the positive number only)
So, the value of a= 16.
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