find the vaalue of a and b in the polynomial x2+(a+1) x+b if the zeroes are 2 and -3
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Answer: a = 3 and b = i was unable to solve
Step-by-step explanation:
x^2 + (a+1)x + b = 0
we know zeros are 2, -3
(2)^2 + (a+1)2 + b = (3)^2 + (a+1)3 +b
4 + 2a + 2 + b = 9 + 3a +3 +b
6+2a+b = 12+3a+b
"b" and "b" gets cancelled
a = 12/6 = 2
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