Question

Find the vale of k , when distance between two points (3,2k)and(4,1)is√10 units

Answer 1

Solution:-

We know that:

Distance between two points

A(a,b) and B(c,d)

=> AB = √(c-a)² +(d-b)²

Here,

According to question.

√10 = √(4-3)² + ( 1-2k)²

=> 10 = 1 + (1-2k)²

=> 9 = (1-2k)²

=> ±3 = (1-2k)

=> 1-2k = 3 and 1-2k= -3

=> -2k = 2 and -2k = -4

=> k = -1 and k = 2

=> k = -1,2 Answer

Answer 2

the correct answer of this question is 1 or 2