Question

find the value accelaration due to gravity "g" on the surface of earth​​

Answer 1

Answer:

9.8m/S2 or approximately 10

Answer 2

Answer:

from 2nd law..

f=m×a

free fall,

f=m×g—1

from universal law of gravitation

f=G=M×m/d²—2..

mg=G=M×m/d²×m

g =G×M/d²..

for object near the earth = the radius of earth R

g=G×M/R²

and value is 9.8m/s²