Math, asked by sweetyvasu, 1 year ago

find the value cos²20+cos²65 whole divided by sin²40+sin²50 and
find the value sin20×cos70+cos20×sin70


raoatchut191: IS THE QUESTION RIGHT
sweetyvasu: ya
raoatchut191: ONCE CROSS CHECK (COS^2*20+COS^2*65)
rishimhaske: wrong que.....it should be
rishimhaske: cos²20+cos²660
rishimhaske: it sould be cos²20+cos²60
sweetyvasu: sry wt u said is correct
manitkapoor2: or if it cos^2(25)+cos^2(65) then rishim is correct
kvnmurty: the angles are 20 and 65 ?

Answers

Answered by rishimhaske
2
Ans of que .2)

we know
sin(90-Ф)=cosФ
so...
sin20=cos70
so,
=sin20×cos70+cos20×sin70
=sin²20+cos²20
by pythagoras identity,
sin²+cos²=1
so
sin20×cos70+cos20×sin70=1
ans of que 1)
=(cos
²20+cos²60)/(sin²40+sin²50)
we know
sin(90-Ф)=cosФ
so
=(cos²70+sin²70)(sin²50+cos²50)
by pythagoras identity,
sin²+cos²=1
so
=1/1
=1








manitkapoor2: which std are u?
rishimhaske: 9 th
rishimhaske: nd u?
manitkapoor2: 8th
manitkapoor2: im my school i will take it just like paper of answers
Anonymous: The answer for Q1 isn't right
sweetyvasu: thn
Anonymous: Can you type the question again in comments?
sweetyvasu: ya
sweetyvasu: cossqare20+cossqare65 whole divided by sinsqare40+sinsquare50
Answered by manitkapoor2
2

 \frac{cos^220+cos^265}{sin^240+sin^250}= \frac{cos^220+cos^265}{sin^240+cos^240}= \frac{cos^220+cos^265}{1}

 \frac{cos^220+cos^265}{1}=  \frac{1.0616284167162193544398746203241}{1}
used a calculator
as sin^2x+cos^2x=1,sin(90-x)=cos(x)
given x lies in first quadrant
sin20(cos70)+sin70(cos(20))=
=(sin20)*(sin(90-70))+cos(20)(cos(90-70))=
sin^220+cos^220=1

manitkapoor2: ???
manitkapoor2: it is correct only
manitkapoor2: according to the question given
sweetyvasu: but i didnot report
manitkapoor2: ok
kvnmurty: it is not right to use calculator.. u need to simply in Sine, cos rations
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