find the value of 100 J on a system which has 20 cm , 250 g and half minute as fundamental units of length, mass and time.
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Ahoy !
Here n 1 = 100 J
M1 = 1 kg
L1 = 1m
T1 = 1 sec
And M2 = 250g
L2 = 20 g
T2 = 30 sec
[ M1 ] ^ 1 [ L1 ] ^ 2 [ T1 ] ^-2 . n2= n1 --------------------------------------
[ M2 ] ^1 [ L2 ]^2 [ T2 ]^-2
Putting value in this formula we get
n2 = 100 [ 1000 / 250 ] x [ 100 / 20 ]^2 x
[ 1 / 30 ] ^ -2
n2 = 100 x 4 x 25 x 900
n2 = 9 x 10^6 new units
May it helpful ^ _ ^
Here n 1 = 100 J
M1 = 1 kg
L1 = 1m
T1 = 1 sec
And M2 = 250g
L2 = 20 g
T2 = 30 sec
[ M1 ] ^ 1 [ L1 ] ^ 2 [ T1 ] ^-2 . n2= n1 --------------------------------------
[ M2 ] ^1 [ L2 ]^2 [ T2 ]^-2
Putting value in this formula we get
n2 = 100 [ 1000 / 250 ] x [ 100 / 20 ]^2 x
[ 1 / 30 ] ^ -2
n2 = 100 x 4 x 25 x 900
n2 = 9 x 10^6 new units
May it helpful ^ _ ^
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Hello !!
Hope it will help you .
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