Math, asked by TrapNation, 1 year ago

trigonometry question
2cos²theta-1/sintheta*costheta = cottheta-tanttheta

Answers

Answered by prajapatyk
2
RHS=cotA-tanA

LHS=(2cos²A-1)/sinAcosA

LHS=(2cos²A-sin²A-cos²A)/sinAcosA

LHS=(cos²A-sin²A)/sinAcosA

LHS=cos²A/sinAcosA-sin²/cosAsinA

LHS=cosA/sinA-sinA/cosA

LHS=cotA-tanA

LHS=RHS
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Answered by Anonymous
1
using trigonometric identities...

we can solve this problem..

see attachment...

__________________

hope it will help u
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