Question

find the value of (2-¹*3-¹)÷2-³​

Answer 1

Answer:

The correct answer is 2^18

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Answer 2

Answer:-

Question:-

To find the value of:

$\mathfrak\red{( {2}^{ - 1} \times {3}^{ - 1} ) \div {2}^{ - 3} }$

Process:-

$\tt{( {2}^{ - 1} \times {3}^{ - 1} ) \div {2}^{ - 3}}$

(Question, first Step)

$\tt{ = ( \frac{1}{2} \times \frac{1}{3} ) \div {2}^{ - 3} }$

(In this step, we have written the fractional form of 2^-1 and 3^-1)

$\tt{= \frac{1}{6} \times \frac{1}{ {2}^{ - 3}} }$

(In this step, we have multiplied 1/2 and 1/3. Before division, a number with numerator 1 is always taken)

$\tt{ = \frac{1}{6} \times \frac{1}{ \frac{1}{ {2}^{3} } } }$

(Placed the value of 2^-3)

$\tt{= \frac{1}{6} \times \frac{ {2}^{3} \times 1}{1} }$

(Preparation for multiplication of 2³ with 1)

$\tt{ = \frac{1}{6} \times {2}^{3}}$

(After multiplication, 2³ is the result)

$\tt{ = \frac{1}{6} \times \frac{2 \times 2 \times 2}{1}}$

(Value of 2³ is put)

$\tt{ = \frac{1}{3} \times 2 \times 2}$

(Cancelled 6 and 2 by 2 and the result is taken)

$\tt{ = \frac{2 \times 2}{3}}$

(Preparation for multiplication)

$\mathfrak\green{ = \frac{4}{3}}$

$\tt\blue{(Result \ is \ found)}$

REQUIRED ANSWER:-

Hence, the value of

$\sf\red{( {2}^{ - 1} \times {3}^{ - 1} ) \div {2}^{ - 3}}$

is,

$\huge\sf\green{ \frac{4}{3} }$