Question

find the value of: 27^-2/3×81^5/4 by (1/3)^-3 with answer 1​

Answer 1

Step-by-step explanation:

$\frac{ {27}^{ - \frac{2}{3} } \times {81}^{ \frac{5}{4} } }{ ({ \frac{1}{3}) }^{ - 3} } \\ = \frac{ {( {3}^{3} )}^{ - \frac{2}{3} } \times {( {3}^{4} )}^{ \frac{5}{4} } }{ \frac{1}{ {3}^{ - 3} } } \\ = \frac{ {3}^{ - 2} \times {3}^{5} }{ {3}^{3} } \\ = {3}^{ - 2} \times {3}^{5} \times {3}^{ - 3} \\ = {3}^{ - 2 + 5 - 3} \\ = {3}^{0} \\ = 1$

hope you get your answer

Answer 2

$\dfrac{ {27}^{ - \frac{2}{3} } \times {81}^{ \frac{5}{4} } }{ ({ \frac{1}{3}) }^{ - 3} }=1$

Step-by-step explanation:

Given : Expression ${27}^{ - \frac{2}{3} } \times {81}^{ \frac{5}{4}$  by  $(\frac{1}{3}) }^{ - 3}$

To find : The value of expression ?

Solution :

The expression is written as,

$\dfrac{ {27}^{ - \frac{2}{3} } \times {81}^{ \frac{5}{4} } }{ ({ \frac{1}{3}) }^{ - 3} }$

$=\frac{ {( {3}^{3} )}^{ - \frac{2}{3} } \times {( {3}^{4} )}^{ \frac{5}{4} } }{ \frac{1}{ {3}^{ - 3} } }$

$=\frac{ {3}^{ - 2} \times {3}^{5} }{ {3}^{3} }$

$= {3}^{ - 2} \times {3}^{5} \times {3}^{ - 3}$

$= {3}^{ - 2 + 5 - 3}$

$= {3}^{0}$

$=1$

Therefore, $\dfrac{ {27}^{ - \frac{2}{3} } \times {81}^{ \frac{5}{4} } }{ ({ \frac{1}{3}) }^{ - 3} }=1$

#Learn more

Solve : 3a + 4/ 2 - 6a = -2/5​

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