Question

Fiñd the value of

27a^3 + 108a^2b + 144ab^2 + 64b^3 if a = 2, b = 3.

Answer 1

$\bold{\boxed{HEY!!!}}$


$<b>{Here is your answer :- }$


27a³ + 108a²b + 144ab² + 64b³


= ( 3a )³ + 3 × 9 × 4 a²b + 3 × 16 × 3 ab² + ( 4b )³


= ( 3a + 4b )³


= [ 3( 2 ) + 4( 3 )]³


= ( 6 + 12 )³


= 18³


= 5832


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Answer 2

$<b><i> the give expression$

= (3a)² + 3(3a)² (4b) + 3(3a) + (4b)² + (4b)³

= (3a + 4b)³ = (3 × 2 + 4 × 3)³

= (6 + 12)³ = 18³

= 5832.

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