Question

Find the value of (3/2+under root 6)^2 (3/2- under root 6)^2

Answer 1

=(9/4+6-3√6)(9/4+6-3√6)
={(9+24+12√6)/4}{(9+24-12√6)/4}
={(33+12√6)/4}{(33-12√6)/4}
=(33/4+12√6/4)(33/4-12√6/4)
=(33/4+3√6)(33/4-3√6)
=1089/16-54
=(1079-864)/16
=225/16
=14.06

Answer 2

accordingly,
(3/2+2.44)^2(3/2-2.44)^2
by using identity, (a+b)^2 * (a-b)^2 
So,
(9/4+6-3√6) * (9/4+6-3√6)
(9+24+12√6)/4 * (9+24-12√6)/4
(33+12√6)/4 * (33-12√6)/4
(33/4+12√6/4) * (33/4-12√6/4)
(33/4+3√6) * (33/4-3√6)
1089/16-54
(1079-864)/16
225/16

thus , your required answer is 225/16
hope i helped u 
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