Question

find the value of 3 underroot 3x-2=4​

Answer 1

$3 \sqrt{3} \times - 2 = - 6 \sqrt{3}$

Answer 2

$3 \sqrt{3 }x - 2 = 4 \\ = > 3 \sqrt{3} x = 4 + 2 \\ = > x = \frac{6}{3 \sqrt{3} } \\ = > x = \frac{2}{ \sqrt{3} } \\ = > x = \frac{2 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } \\ = > x = \frac{2 \sqrt{3} }{3}$

Hope it'll help.... :-)