Find the value of (5a-7b)^3+(9c-5a)^3+(7b-9c)^3
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Answered by
29
this is somewhat a long solution bt u can do this by using this formula..... a³ + b³ + c³ = (a + b + c) (a² + b² + c²– ab – bc – ca) + 3abc.
I hope this will help u..
I hope this will help u..
Answered by
59
Thanks for a BRAINLY question!!!!
We have, (5a-7b)^3+(9c-5a)^3+(7b-9c)^3
Let us consider A = (5a-7b)
B = (9c-5a)
C = (7b-9c)
Now, A+B+C = (5a-7b)+(9c-5a)+(7b-9c) = 0
Since, A+B+C= 0
then, A^3 + B^3 + C^3 = 3ABC
This means,
(5a-7b)^3+(9c-5a)^3+(7b-9c)^3
= 3ABC
= 3 {(5a-7b)(9c-5a)(7b-9c)}
Hope it helps!!!!
We have, (5a-7b)^3+(9c-5a)^3+(7b-9c)^3
Let us consider A = (5a-7b)
B = (9c-5a)
C = (7b-9c)
Now, A+B+C = (5a-7b)+(9c-5a)+(7b-9c) = 0
Since, A+B+C= 0
then, A^3 + B^3 + C^3 = 3ABC
This means,
(5a-7b)^3+(9c-5a)^3+(7b-9c)^3
= 3ABC
= 3 {(5a-7b)(9c-5a)(7b-9c)}
Hope it helps!!!!
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