Math, asked by so19, 1 year ago

find the value of (7/cot^2-7/cos^2)

Answers

Answered by Thatsomeone
25
7 / cot ^2A - 7 / cos ^2A

= 7 tan^2 A - 7 / cos ^2 A

= 7sin^2 A / cos^2 A - 7 / cos ^2 A

= 7 sin^2 A - 7 / cos ^2 A

= 7 ( sin^2 A - 1 ) / cos^2 A

= 7 cos^2 A / cos^2 A

= 7

so your required answer is 7
Answered by sireeshasuresh2003
5

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