Find the value of √7+ sqare 48
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Answer:
4+3 + square root of 4 * 12
4+3 +2*√12
(√4)^2 +2*√12 + (√3)^2 =( √4)^2 +2*√4*√3 +(√3)^2
(a+b)^2 = a^2+2ab + b^2
(√4+√3)^2
7+√48 = (√4+√3)^2
Square root of 7 +√48 = √4+√3
√4 = 2
2+√3
Ans : 2+√3
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