Question

what is the energy dissipated in a resistor of 10 ohm when 1 ampere of current is passed through it for 2 minutes ( at the back of the book answer is given 1200 J ) please answer plz fast no spam

Answer 1

GIVEN:

resistance = 10 ohm

current = 1 ampere

time = 2 min =2×60=120 sec

FORMULA :

P = E / t

we know that ,

P = I ² R

energy is dissipated in the form of Heat so now the equation can be written as

P = H /t

H = I ² R t

Here ,

P = power

H = Heat

I = current

t = time

SOLUTION :

H= I² R t

H = 1×10×2×60

H =1200J

Answer 2

Answer:

Power is calculated in one of the following way for resistor ( V: voltage, I :Current, R : Resistance )

Power = R × I × I

Power = (V ×V) /R

Power = V × I

In your case, power is 4 × 15×15 = 900 Watt

So make sure your resistor can handle that and you need to have some heat sink for that