Math, asked by shanaya1219, 1 year ago

Find the value of a and b if √3-1 /√3+1 = a+6 √3
pls tell write solutions ..

Answers

Answered by Anonymous
2
⭐⭐Hello friend...Ur answer is here⤵⤵

 \frac{ \sqrt{3 } - 1}{ \sqrt{3} + 1} = a + b \sqrt{3} \\ \\ multiplying \: by \: \sqrt{3} - 1 \: in \: numerator \: and dinominator \\ \\ \frac{ (\sqrt{3} - 1)( \sqrt{3} - 1)}{ (\sqrt{3} + 1)( \sqrt{3} - 1) } \\ \\ \frac{3 + 1 - 2 \sqrt{3} } {3 - 1} \\ \\ \frac{4 - 2 \sqrt{3} }{2} \\ \\ 2 - \sqrt{3} \\ \\ compare \: with \: a + b \sqrt{3} \\ \\ a = 2 \: and \: b = -1

I HOPE IT IS HELPFUL TO YOU ☺
Answered by Panzer786
5
Hiii friend,

=> ✓3-1/✓3+1

=> ✓3-1/✓3+1 × ✓3-1/✓3-1

=> (✓3-1)(✓3-1)/(✓3-1)(✓3+1)

=> (✓3-1)² / (✓3)² - (1)²

=> (✓3)² + (1)² - 2 × ✓3 × 1/3-1

=> 3+1-2✓3/2

=> 4-2✓3/2

=> 2(2-✓3)/2 => 2-✓3

LHS = RHS

2-✓3 = a+b✓3

A = 2 and B = -1


HOPE IT WILL HELP YOU...... :-)
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