Question

Find the value of A and B of the number 4AB8 (A ,B are digits) which is divisible by 2,3,4,6,8 & 9

Answer 1

HI BRO
If we consider every counting table from 2 to 9 we will get 72 common in every COUNTING TABLE
so THE VALUE OF A=7 and B=2
HOPE IT WILL HELP U
THANK U☺

Answer 2

Answer:

A=9, B=6

Step-by-step explanation:

unit digit is 8

so, 4AB8 os divisible by 2

sum of the digits should be a multiple of 3

4+A+B+8 is multiple of 3

A may be 2,4,6 or 9

B may be 2,4,6 or 9

last 2 digits should be a multiple of 4

so, B may be 2,4 or 6

4AB8 is divisible by both 2 and 3 so it is also divisible by 6

last 3 digits should be multiple of 8

so, AB8 may be 248,448,648,928 or 968

sum of the digits should be a multiple of 9

So, A=9, B=6