Question

Find the value of 'a' if the point (-6, 3) lies on the locus x² = 4ay.

Answer 1

Your answer 'a' = 3

$\bf{step\:wise\:explanation}$

P= (-6 , 3 )

Absisca (x - point) = -6

Ordinate (y-point) = 3 .

Equation -:

x^2 = 4ay

(-6)^2 = 4 a ×3

Now, we know that square of any negative number is always positive. So (-6)^2 = 36 .

36 = 12 a

36/12 = a

3 = a

$\bf{So \: value\: of \: a \: = \: 3 }$

$\bf{Hope\:it\:helps}$