Math, asked by sammy45, 1 year ago

find the value of a in the following =6/3 root 2 - 2 root 3 = 3 root 2 - a root 3

Answers

Answered by snehitha2
346
6/(3√2-2√3)

Here we have to rationalise the denominator,

Rationalising factor=(3√2+2√3)

=6/(3√2-2√3)×(3√2+2√3)/(3√2+2√3)

=6(3√2+2√3)/(3√2-2√3)(3√2+2√3)

=(18√2+12√3)/[(3√2)²-(2√3)²]

=(18√2+12√3)/(9(2)-4(3))

=(18√2+12√3)/18-12

=(18√2+12√3)/6

=(18√2/6)+(12√3/6)

=3√2+2√3

=3√2-(-2√3)

Compare this with 3√2-a√3

3√2-(-2√3)=3√2-a√3

Therefore, a= -2

Hope it helps...

sivaprasath: the denominator is already rationalised,3√2+2√3 is completed,,..??
sivaprasath: hey,3√2+2√3/1=3√2+2√3 isn't it rationalised?
sivaprasath: ok,I will study back and come,.
sivaprasath: ok,looks like I'm probably confused,I will check and COME BACK,.
sivaprasath: ok,,I'm sure about it,... the roots make the answer an irrational one.Then,3√2+2√3=(3x1.414)+(2x1.732) = 4.242+3.464=7.706
sivaprasath: then,now it is rational number(just an approx.),.
Answered by EmmaRoseJack
183

Answer is shown in picture:

a=-2

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