Question

find the value of a to b

Answer 1

...........#hope it helps

Answer 2

Hey buddy !


Here is yr answer.....


$= > \frac{5 + 3 \sqrt{3} }{7 + 4 \sqrt{3} } = a + b \sqrt{3} \\ \\ = > \frac{5 + 3 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } = a + b \sqrt{3} \\ \\ = > \frac{35 - 20 \sqrt{3} + 21 \sqrt{3} - 36}{49 - 48} = a + b \sqrt{3} \\ \\ = > - 1 + 1 \sqrt{3} = a + b \sqrt{3} \\ \\ therefore \: ..... \: a = - 1 \: \:and \: \: \: b = 1$


Hope it hlpz...