find the value of angle angle abc if ac =cd
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Answer:
57.5°
Step-by-step explanation:
Image is very blur. So I am answering as a hit in dark.
In ∆ABC,
Angle ABC = Angle ACB = x
65° + x + x = 180°
2x = 115°
x = 115°/2
x = 57.5°
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Answer:
In ∆ADC Angle ADC = 30°
therefore, Angle DAC= 30°
thus, angle ACD is 120°
since angle BCA + angle DCA = 180°
Therefore, angle BCA = 60°
now in ∆ABC ,
angle ABC + angle CAB + Angle BCA =180°
thus, angle ABC = 180°- 65°-60°= 55°
thus, angle ABC is 55°
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