Question

find the value of angle angle abc if ac =cd​

Answer 1

Answer:

57.5°

Step-by-step explanation:

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In ∆ABC,

Angle ABC = Angle ACB = x

65° + x + x = 180°

2x = 115°

x = 115°/2

x = 57.5°

Answer 2

Answer:

In ∆ADC Angle ADC = 30°

therefore, Angle DAC= 30°

thus, angle ACD is 120°

since angle BCA + angle DCA = 180°

Therefore, angle BCA = 60°

now in ∆ABC ,

angle ABC + angle CAB + Angle BCA =180°

thus, angle ABC = 180°- 65°-60°= 55°

thus, angle ABC is 55°