find the value of angle BCE in a triangle
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Answer:
the answer is c 80 degrees because angle a = angle b,since their oppositesides are equal.then angle acb =100 and then acb + bce =180 then bce = 80
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Answer:
80°
Step-by-step explanation:
As two sides of a triangle are 4cm it is a isosceles triangle
so angle opposite to equal sides are equal
thus angle ABC = angle BAC
therefore angle ABC =40°
now
<ACB+ <ABC+ <BAC =180°---------(Angle sum property of a triangle)
<ACB+40 +40 =180
<ACB = 180-80
<ACB=100°
NOW
<ACB+ <BCE= 180°-----(AS the angles are in linear pair)
100+ <BCE =180
Therefore angle BCE is equal to 80°
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