Math, asked by vvarshashiva, 8 months ago

find the value of angle BCE in a triangle​

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Answers

Answered by rishijhaver
0

Answer:

the answer is c 80 degrees because angle a = angle b,since their oppositesides are equal.then angle acb =100 and then acb + bce =180 then bce = 80

Answered by misstalent
0

Answer:

80°

Step-by-step explanation:

As two sides of a triangle are 4cm it is a isosceles triangle

so angle opposite to equal sides are equal

thus angle ABC = angle BAC

therefore angle ABC =40°

now

<ACB+ <ABC+ <BAC =180°---------(Angle sum property of a triangle)

<ACB+40 +40 =180

<ACB = 180-80

<ACB=100°

NOW

<ACB+ <BCE= 180°-----(AS the angles are in linear pair)

100+ <BCE =180

Therefore angle BCE is equal to 80°

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