Find the value of b if x cube minus bx square + 3 BX minus b is exactly divisible by X - 3
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Given that (x - 3) is the factor
So, x - 3 = 0
x = 0 + 3
x = 3
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Putting the value of x in given equation,
x^3 - bx^2 + 3bx - b = 0
(3)^3 - b(3)^2 + 3b(3) - b = 0
27 - 9b + 9b - b =0
27 - b = 0
27 = b
i hope this will help you
(-:
So, x - 3 = 0
x = 0 + 3
x = 3
---------------------------------------
Putting the value of x in given equation,
x^3 - bx^2 + 3bx - b = 0
(3)^3 - b(3)^2 + 3b(3) - b = 0
27 - 9b + 9b - b =0
27 - b = 0
27 = b
i hope this will help you
(-:
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Example
2^3 = 2*2*2 = 8
2^3 = 2*2*2 = 8
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