Question

Find the value of b so that the point (4,b) lies on the line 3x-2y=5
a.2/7
b.7/2
c.5/12
d.12/5​

Answer 1

ANSWER

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a line

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m=

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−2

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4 =−1

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4 =−1⇒y−4=−1(x−2)

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4 =−1⇒y−4=−1(x−2)⇒y+x−6=0

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4 =−1⇒y−4=−1(x−2)⇒y+x−6=0solving eq(1) 3x+2y+10=0 and wq(2) y+x−6=0 we will get x=−22,y=28

ANSWER∣PA−PB∣ is maximum when P,A,B lies on a lineso equation of line containing A,B is y−4=m(x−2)m= 4−22−4 =−1⇒y−4=−1(x−2)⇒y+x−6=0solving eq(1) 3x+2y+10=0 and wq(2) y+x−6=0 we will get x=−22,y=28so point P will be (−22,28

Step-by-step explanation:

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