Question

find the value of c for which the pair of equations cx-y=2 and 6x-2y=4 will have infinitely many solution​

Answer 1

Answer:

since the equations have infinitely many solutions

therefore

A1/a2 = b1/ b2 = c1 / c2

hence

c/6=-1/-2=. -2/-4

c/6=1/2=1/2

therefore

c=3

Answer 2

For no value of c the pair of equations will have infinitely many solutions.

Step-by-step explanation:

Given : The pair of equation $cx-y=2$ and  $6x-2y=3$ will have infinitely many solution.

To find : The value of 'c'?

Solution :

Condition for infinitely many solutions is

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

Given lines are $cx-y=2$ and  $6x-2y=3$

So, $a_1=c,b_1=-1,c_1=-2,a_2=6,b_2=-2,c_2=-3$

Substitute in the condition,

$\frac{c}{6}=\frac{-1}{-2}=\frac{-2}{-3}$

$\frac{c}{6}=\frac{1}{2}=\frac{2}{3}$

Take first two,

$\frac{c}{6}=\frac{1}{2}$

Solve,

$c=3$

Take first and last,

$\frac{c}{6}=\frac{2}{3}$

Solve,

$c=4$

Since, c has different values.

Hence, For no value of c the pair of equations will have infinitely many solutions.

#Learn more

Solve the following pair of linear equati

method:

(1) 4+ y = 5 and 2x – 3y = 4

​https://brainly.in/question/9653442