Find the value of [cot(20-theta)+tan(70+they)/sin(70+they)]×sin(20-theta)
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Let cos(20-tetha) remain same..
Let us change Sin(70-tetha)
As we know that...
Sin(90-tetha)=Cos tetha
Sin(70-tetha)=Cos[90-(70+tetha)]
=Cos(20+tetha)
Cos(20-tetha) - Cos(20-tetha) = 0
Hence proved...
Step-by-step explanation:
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