Question

find the value of if3+2√3÷3-2√3=a+b√3​

Answer 1

Answer:

$\frac{3 + 2 \sqrt{3} }{3 - 2 \sqrt{3} }$

$\frac{3 + 2 \sqrt{3} }{3 - 2 \sqrt{3} } \times \frac{3 + 2 \sqrt{3} }{3 + 2 \sqrt{3} }$

Rationalizing the denominator

$\frac{ 9 + 6 \sqrt{3 } + 6 \sqrt{3 } + 12}{ {(3)}^{2} - {(2 \sqrt{3)} }^{2} }$

$\frac{12 \sqrt{3 } + 21}{9 - 12}$

$\frac{12 \sqrt{3} + 21}{ - 3}$

-(7+4 root3)

$- 7 - 4 \sqrt{3}$

a=-7 b=-4

HOPE THIS WILL HELP YOU