Question

Find the value of k for the quadratic equation 2 X squre + kx + 3 equal to zero so that it has two equal roots

Answer 1

here is your answer . hope it will be useful to you

Answer 2

Answer:

k = 2√6  ,  roots are =  - √3/√2

k = -2√6  ,  roots are =  √3/√2

Step-by-step explanation:

2X² + kX + 3 = 0

will have equal roots if

k² - 4(2)(3) = 0

k² = 24

k = +/- 2√6

so

Case 1

2X² + 2√6x + 3 = 0

2X² + √6x + √6x + 3 = 0

√2X(√2X + √3) + √3 (√2X +√3) = 0

(√2X +√3)(√2X +√3) = 0

(√2X + √3)^2 = 0

X = - (√3/√2)

Case 2

2X² - 2√6x + 3 = 0

2X² - √6x - √6x + 3 = 0

√2X(√2X - √3) - √3 (√2X - √3) = 0

(√2X -√3)(√2X -√3) = 0

(√2X - √3)^2 = 0

X = √3/√2